mirror of
https://github.com/deepseek-ai/DeepSeek-Math
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121 lines
4.4 KiB
Python
121 lines
4.4 KiB
Python
from .few_shot_prompting import FewShotPrompting
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few_shot_prompt = """
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Problem:
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Subproblem 0: What is the net charge of arginine in a solution of $\\mathrm{pH} 1.0$?
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Please format your answer as +n or -n.
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Solution:
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The answer is +2.
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Final answer: The final answer is $\\boxed{+2}$. I hope it is correct.
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Problem:
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Subproblem 0: Let $z = 1 + \\sqrt{3} i$. Find $a, b$ that satisfy the equation
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$z^4 = a + bi$. Express your answer as the ordered pair $(a,b)$.
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Solution:
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$z^{4}$ has argument $4 \\pi / 3$ and radius 16 , so it's equal to $-8-8 \\sqrt{3} i$.
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Thus $a = -8, b = -8\\sqrt 3$, and our answer is $(-8, -8\\sqrt{3})$.
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Final answer: The final answer is $\\boxed{(-8, -8\\sqrt{3})}$. I hope it is correct.
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Problem:
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Preamble: For each Laplace Transform \\(Y(s)\\), find the function \\(y(t)\\):
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Subproblem 0:
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\\[Y(s)=\\frac{1}{(s+a)(s+b)}\\]
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Solution:
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We can simplify with partial fractions:
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\\[Y(s)=\\frac{1}{(s+a)(s+b)}=\\frac{C}{s+a}+\\frac{D}{s+b}\\]
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find the constants
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\\(C\\) and \\(D\\) by setting \\(s=-a\\) and \\(s=-b\\)
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\\[
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\\begin{aligned}
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\\frac{1}{(s+a)(s+b)} &=\\frac{C}{s+a}+\\frac{D}{s+b} \\\\
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1 &=C(s+b)+D(s+a) \\\\
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C &=\\frac{1}{b-a} \\\\
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D &=\\frac{1}{a-b}
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\\end{aligned}
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\\]
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therefore
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\\[
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Y(s)=\\frac{1}{b-a} \\frac{1}{s+a}-\\frac{1}{b-a} \\frac{1}{s+b}
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\\]
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By looking up the inverse Laplace Transform of \\(\\frac{1}{s+b}\\), we find the total
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solution \\(y(t)\\)
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\\[
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y(t)=\\frac{e^{-a t}-e^{-b t}}{b-a}
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\\].
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Final answer: The final answer is $\\boxed{\\frac{e^{-a t}-e^{-b t}}{b-a}}$. I hope it is correct.
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Problem:
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Preamble: The following subproblems refer to the differential equation
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$\\ddot{x}+b \\dot{x}+x=0$.
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Subproblem 0: What is the characteristic polynomial $p(s)$ of
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$\\ddot{x}+b \\dot{x}+x=0$?
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Solution:
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The characteristic polynomial is $p(s)=s^{2}+b s+1$.
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Final answer: The final answer is $\\boxed{s^{2}+b s+1}$. I hope it is correct.
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""".strip()
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few_shot_prompt = """
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Problem:
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Subproblem 0: What is the net charge of arginine in a solution of $\\mathrm{pH} 1.0$?
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Please format your answer as +n or -n.
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Solution:
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The answer is +2.
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Final answer: The final answer is +2. I hope it is correct.
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Problem:
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Subproblem 0: Let $z = 1 + \\sqrt{3} i$. Find $a, b$ that satisfy the equation
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$z^4 = a + bi$. Express your answer as the ordered pair $(a,b)$.
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Solution:
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$z^{4}$ has argument $4 \\pi / 3$ and radius 16 , so it's equal to $-8-8 \\sqrt{3} i$.
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Thus $a = -8, b = -8\\sqrt 3$, and our answer is $\\boxed{(-8, -8\\sqrt{3})}$.
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Final answer: The final answer is (-8, -8\\sqrt{3}). I hope it is correct.
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Problem:
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Preamble: For each Laplace Transform \\(Y(s)\\), find the function \\(y(t)\\):
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Subproblem 0:
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\\[Y(s)=\\boxed{\\frac{1}{(s+a)(s+b)}}\\]
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Solution:
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We can simplify with partial fractions:
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\\[Y(s)=\\frac{1}{(s+a)(s+b)}=\\frac{C}{s+a}+\\frac{D}{s+b}\\]
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find the constants
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\\(C\\) and \\(D\\) by setting \\(s=-a\\) and \\(s=-b\\)
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\\[
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\\begin{aligned}
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\\frac{1}{(s+a)(s+b)} &=\\frac{C}{s+a}+\\frac{D}{s+b} \\\\
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1 &=C(s+b)+D(s+a) \\\\
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C &=\\frac{1}{b-a} \\\\
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D &=\\frac{1}{a-b}
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\\end{aligned}
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\\]
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therefore
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\\[
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Y(s)=\\frac{1}{b-a} \\frac{1}{s+a}-\\frac{1}{b-a} \\frac{1}{s+b}
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\\]
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By looking up the inverse Laplace Transform of \\(\\frac{1}{s+b}\\), we find the total
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solution \\(y(t)\\)
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\\[
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y(t)=\\boxed{\\frac{1}{b-a}\\left(e^{-a t}-e^{-b t}\\right)}
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\\].
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Final answer: The final answer is \\[\\frac{1}{b-a}\\left(e^{-a t}-e^{-b t}\\right)\\]. I hope it is correct.
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Problem:
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Preamble: The following subproblems refer to the differential equation
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$\\ddot{x}+b \\dot{x}+x=0$.
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Subproblem 0: What is the characteristic polynomial $p(s)$ of
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$\\ddot{x}+b \\dot{x}+x=0$?
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Solution:
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The characteristic polynomial is $p(s)=\\boxed{s^{2}+b s+1}$.
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Final answer: The final answer is $s^{2}+b s+1$. I hope it is correct.
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""".strip()
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class OCWCoursesPrompt(FewShotPrompting):
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def __init__(self):
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super().__init__()
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def format_prompt(self, task_input, task_output):
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prompt = f"{few_shot_prompt}\n\nProblem:\n{task_input}\nSolution:\n{task_output}"
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return prompt.rstrip()
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def stop_words(self):
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return ["\nProblem:"]
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