mirror of
https://github.com/deepseek-ai/DeepSeek-Math
synced 2024-11-22 11:38:17 +00:00
419 lines
11 KiB
Python
419 lines
11 KiB
Python
from .few_shot_prompting import FewShotPrompting
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few_shot_prompt = {
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'numbertheory': """Informal:
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(*### Problem
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Find the minimum value of $\\frac{9x^2\\sin^2 x + 4}{x\\sin x}$ for $0 < x < \\pi$. Show that it is 12.
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### Solution
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Let $y = x \\sin x$. It suffices to show that $12 \\leq \\frac{9y^2 + 4}{y}.
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It is trivial to see that $y > 0$.
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Then one can multiply both sides by $y$ and it suffices to show $12y \\leq 9y^2 + 4$.
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This can be done by the sum of squares method.*)
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Formal:
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theorem aime_1983_p9:
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fixes x::real
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assumes "0<x" "x<pi"
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shows "12 \\<le> ((9 * (x^2 * (sin x)^2)) + 4) / (x * sin x)"
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proof -
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(* Let $y = x \\sin x$. *)
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define y where "y=x * sin x"
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(* It suffices to show that $12 \\leq \\frac{9y^2 + 4}{y}. *)
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have "12 \\<le> (9 * y^2 + 4) / y"
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proof -
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(* It is trivial to see that $y > 0$. *)
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have c0: "y > 0"
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sledgehammer
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(* Then one can multiply both sides by $y$ and it suffices to show $12y \\leq 9y^2 + 4$. *)
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have "(9 * y^2 + 4) \\<ge> 12 * y"
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sledgehammer
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then show ?thesis
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sledgehammer
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qed
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then show ?thesis
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sledgehammer
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qed
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Informal:
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(*### Problem
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Find the greatest common factor of 180 and 168. Show that it is 12.
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### Solution
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This is true by simple evaluation.*)
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Formal:
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theorem mathd_numbertheory_188:
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"gcd 180 168 = (12::nat)"
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sledgehammer
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Informal:
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(*### Problem
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Show that for positive integer n, 2 divides $4^n$.
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### Solution
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Since n is positive, we can find a natural number m where $m+1=n$.
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Then we can show that 2 divides $4^{m+1}$. The conclusion thus follows.*)
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Formal:
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theorem numbertheory_2dvd4expn:
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fixes n :: nat
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assumes h0 : "n \\<noteq> 0"
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shows "(2::nat) dvd 4^n"
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proof -
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obtain m::nat where c0: "m+1=n"
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sledgehammer
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have "(2::nat) dvd 4^(m+1)" sledgehammer
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then show ?thesis unfolding c0 sledgehammer
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qed
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Informal:
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(*### Problem
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What is the remainder when $1 + 2 + 3 + 4 + \\dots + 9 + 10$ is divided by 9? Show that it is 1.
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### Solution
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This is true by simple evaluation.*)
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Formal:
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theorem mathd_numbertheory_466:
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"(\\<Sum> k< 11. k) mod 9 = (1::nat)"
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sledgehammer
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Informal:
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(*### Problem
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If $321_{b}$ is equal to the base 10 integer 57, find $b$ given that $b>0$. Show that it is 4.
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### Solution
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Converting $321_{b}$ to base 10 and setting it equal to 57, we find that \\begin{align*} 3(b^2)+2(b^1)+1(b^0)&=57
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\\\\ 3b^2+2b+1&=57
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\\\\\\Rightarrow\\qquad 3b^2+2b-56&=0
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\\\\\\Rightarrow\\qquad (3b+14)(b-4)&=0
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\\end{align*}This tells us that $b$ is either $-\\frac{14}{3}$ or $4$. We know that $b>0$, so $b=4$.*)
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Formal:
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theorem mathd_numbertheory_48:
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fixes b :: real
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assumes h0 : "0<b"
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and h1 : "3 * b^2 + 2 * b + 1 = 57"
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shows "b=4"
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proof -
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(* Converting $321_{b}$ to base 10 and setting it equal to 57, we find that \\begin{align*} 3(b^2)+2(b^1)+1(b^0)&=57
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\\\\ 3b^2+2b+1&=57
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\\\\\\Rightarrow\\qquad 3b^2+2b-56&=0
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\\\\\\Rightarrow\\qquad (3b+14)(b-4)&=0
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\\end{align*} *)
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have "0 = 3 * b^2 + 2 * b -56" using h1 sledgehammer
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also have "... = (3*b+14)*(b-4)" sledgehammer
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finally have "0 = (3*b+14)*(b-4)" sledgehammer
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(* This tells us that $b$ is either $-\\frac{14}{3}$ or $4$. *)
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then have "b = -14/3 ∨ b=4" sledgehammer
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(* We know that $b>0$, so $b=4$. *)
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then show ?thesis using h0 sledgehammer
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qed
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Informal:
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(*### Problem
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When Rachel divides her favorite number by 7, she gets a remainder of 5. What will the remainder be if she multiplies her favorite number by 5 and then divides by 7? Show that it is 4.
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### Solution
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Let $n$ be Rachel's favorite number.
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Then $n \\equiv 5 \\pmod{7}$, so $5n \\equiv 5 \\cdot 5 \\equiv 25 \\equiv 4 \\pmod{7}$.
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*)
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Formal:
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theorem mathd_numbertheory_335:
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fixes n :: nat
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assumes h0 : "n mod 7 = 5"
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shows "(5 * n) mod 7 = 4"
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proof -
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(* Then $n \\equiv 5 \\pmod{7}$, so $5n \\equiv 5 \\cdot 5 \\equiv 25 \\equiv 4 \\pmod{7}$. *)
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have c0:"(5 * n) mod 7 = (5 * 5) mod 7" using h0
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sledgehammer
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then have "\\<dots> = 4" sledgehammer
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then have "(5 * n) mod 7 = 4" using c0 sledgehammer
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then show ?thesis sledgehammer
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qed
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Informal:
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(*### Problem
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What positive two-digit integer is exactly twice the sum of its digits? Show that it is 18.
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### Solution
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We simplify $10a + b = 2(a+b)$ to get $8a = b$.
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Since $a$ is at least 1, $b$ is at least 8.
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We know $b$ is 8 since $8a = b$ and $a$ is a natural number.
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Hence $a$ is 1.
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The two-digit integer is hence $18$.
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*)
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Formal:
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theorem mathd_numbertheory_284:
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fixes a b :: nat
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assumes h0 : "1\\<le>a \\<and> a \\<le>9 \\<and> b \\<le>9"
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and h1 : "10 * a + b = 2 * (a+b)"
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shows "10 * a + b = 18"
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proof -
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(* We simplify $10a + b = 2(a+b)$ to get $8a = b$. *)
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have c0: "8 * a = b" using h1 sledgehammer
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(* Since $a$ is at least 1, $b$ is at least 8. *)
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hence "b \\<ge> 8" using h0 sledgehammer
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(* We know $b$ is 8 since $8a = b$ and $a$ is a natural number. *)
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hence c1:"b = 8" using h0 c0
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sledgehammer
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(* Hence $a$ is 1. *)
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hence "a = 1" using c0 sledgehammer
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(* The two-digit integer is hence $18$. *)
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then show ?thesis using c1 sledgehammer
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qed
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""".strip(),
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"other": """Informal:
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(*### Problem
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Find the minimum value of $\\frac{9x^2\\sin^2 x + 4}{x\\sin x}$ for $0 < x < \\pi$. Show that it is 12.
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### Solution
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Let $y = x \\sin x$. It suffices to show that $12 \\leq \\frac{9y^2 + 4}{y}.
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It is trivial to see that $y > 0$.
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Then one can multiply both sides by $y$ and it suffices to show $12y \\leq 9y^2 + 4$.
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This can be done by the sum of squares method.*)
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Formal:
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theorem aime_1983_p9:
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fixes x::real
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assumes "0<x" "x<pi"
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shows "12 \\<le> ((9 * (x^2 * (sin x)^2)) + 4) / (x * sin x)"
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proof -
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(* Let $y = x \\sin x$. *)
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define y where "y=x * sin x"
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(* It suffices to show that $12 \\leq \\frac{9y^2 + 4}{y}. *)
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have "12 \\<le> (9 * y^2 + 4) / y"
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proof -
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(* It is trivial to see that $y > 0$. *)
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have c0: "y > 0"
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sledgehammer
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(* Then one can multiply both sides by $y$ and it suffices to show $12y \\leq 9y^2 + 4$. *)
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have "(9 * y^2 + 4) \\<ge> 12 * y"
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sledgehammer
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then show ?thesis
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sledgehammer
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qed
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then show ?thesis
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sledgehammer
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qed
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Informal:
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(*### Problem
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Show that for any four complex numbers a, b, c, and d, $(a-d)(a-c)(a-b) = -(((a^2 - a(b+c)) + bc) * d) + (a^2 - a(b+c) + bc) * a$.
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### Solution
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We first see that $a^2 = a * a$ trivially.
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Unfolding this, the main equation holds true when terms are rearranged.*)
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Formal:
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theorem algebra_3rootspoly_amdtamctambeqnasqmbpctapcbtdpasqmbpctapcbta:
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fixes a b c d :: complex
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shows "(a-d) * (a-c) * (a-b) = -(((a^2 - (b+c) * a) + c * b) * d) + (a^2 - (b+c) * a + c * b) * a"
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proof -
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(* We first see that $a^2 = a * a$ trivially. *)
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have t0: "a^2 = a * a"
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using power2_eq_square
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sledgehammer
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(* Unfolding this, the main equation holds true when terms are rearranged. *)
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show ?thesis unfolding t0
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sledgehammer
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qed
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Informal:
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(*### Problem
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Find the greatest common factor of 180 and 168. Show that it is 12.
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### Solution
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This is true by simple evaluation.*)
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Formal:
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theorem mathd_numbertheory_188:
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"gcd 180 168 = (12::nat)"
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sledgehammer
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Informal:
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(*### Problem
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For how many positive integers $n$ is $n^2 - 3n + 2$ a [[prime]] number?
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$\\mathrm{(A)}\\ \\text{none}
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\\qquad\\mathrm{(B)}\\ \\text{one}
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\\qquad\\mathrm{(C)}\\ \\text{two}
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\\qquad\\mathrm{(D)}\\ \\text{more\\ than\\ two,\\ but\\ finitely\\ many}
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\\qquad\\mathrm{(E)}\\ \\text{infinitely\\ many}$ Show that it is \\mathrm{(B)}\\ \\text{one}.
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### Solution
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Factoring, we get $n^2 - 3n + 2 = (n-2)(n-1)$.
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Either $n-1$ or $n-2$ is odd, and the other is even.
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Their product must yield an even number.
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The only prime that is even is $2$, which is when $n$ is $3$ or $0$.
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Since $0$ is not a positive number, the answer is $\\mathrm{(B)}\\ \\text{one}$.*)
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Formal:
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theorem amc12b_2002_p3:
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fixes n ::nat
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assumes "n>0"
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and prime:"prime (n^2+2-3*n)"
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shows "n=3"
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proof -
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have "n>2"
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proof (rule ccontr)
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assume "\\<not> 2 < n"
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then have "n=1 \\<or> n=2" using \\<open>n>0\\<close> sledgehammer
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then show False using prime[THEN prime_gt_1_nat]
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sledgehammer
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qed
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(* Factoring, we get $n^2 - 3n + 2 = (n-2)(n-1)$. *)
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then have "n^2+2-3*n = (n-1) * (n-2)"
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unfolding power2_eq_square
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sledgehammer
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(* Either $n-1$ or $n-2$ is odd, and the other is even.
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Their product must yield an even number.
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The only prime that is even is $2$, which is when $n$ is $3$ or $0$.
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Since $0$ is not a positive number, the answer is $\\mathrm{(B)}\\ \\text{one}$.*)
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then have "prime ((n-1) * (n-2))"
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using prime sledgehammer
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then have "n-1=1 \\<or> n-2 = 1"
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using prime_product sledgehammer
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with \\<open>n>2\\<close>
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show "n=3" sledgehammer
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qed
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Informal:
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(*### Problem
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For a positive real number a, show that $10a\\leq 28a^2+1$.
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### Solution
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It suffices to show $0\\leq 28a^2 - 10a + 1$.
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First, consider completing the square for $28a^2 - 10a$ and observe that $(a - \\frac{5}{28})^2 = a^2 - \\frac{10}{28}a + (5/28)^2$.
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Since $0\\leq (a - \\frac{5}{28})^2$, we have $0\\leq a^2 - \\frac{10}{28}a + (5/28)^2$.
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Multiplying by 28 and simplifying terms gives $0\\leq 28*a^2 - 10*a + (25/28)$.
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Since $25/28 < 1$, the result follows.*)
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Formal:
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theorem algebra_binomnegdiscrineq_10alt28asqp1:
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fixes a :: real
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shows "10 * a \\<le> 28 * a^2 + 1"
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proof -
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(* it suffices to show $0\\leq 28a^2 - 10a + 1$ *)
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have c0: "0 \\<le> 28*a^2 - 10*a + 1"
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proof -
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(* observe that $(a - \\frac{5}{28})^2 = a^2 - \\frac{10}{28}a + (5/28)^2$ *)
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have c1: "(a - (5/28))^2 = a^2 - 10/28*a + (5/28)^2"
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sledgehammer
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(* we have $0\\leq a^2 - \\frac{10}{28}a + (5/28)^2$ *)
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then have c2: "0 \\<le> a^2 - 10/28*a + (5/28)^2" using c1
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sledgehammer
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(* Multiplying by 28 and simplifying terms gives $0\\leq 28*a^2 - 10*a + (25/28)$ *)
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then have c3: "0 \\<le> 28*a^2 - 10*a + 28*((5/28)^2)" using c2
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sledgehammer
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then have c4: "0 \\<le> 28*a^2 - 10*a + 28*((5/28)*(5/28))" using c3
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sledgehammer
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then have c5: "0 \\<le> 28*a^2 - 10*a + (25/28)" using c4
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sledgehammer
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(* Since $25/28 < 1$, the result follows. *)
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then show ?thesis using c5
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sledgehammer
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qed
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then show ?thesis
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sledgehammer
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qed
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Informal:
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(*### Problem
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Show that for any complex number a, $(a-10)(a+11) = a^2 + a - 110$.
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### Solution
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We first expand all terms of the left hand side to get $a^2 - 10a + 11a - 10*11$.
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This equals $a^2 + a - 10*11 = a^2 + a - 110$.*)
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Formal:
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theorem algebra_2rootsintpoly_am10tap11eqasqpam110:
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fixes a :: complex
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shows "(a-10) * (a+11) = a^2 + a -110"
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proof -
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(* We first expand all terms of the left hand side to get $a^2 - 10a + 11a - 10*11$. *)
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have "(a-10) * (a+11) = a^2 - 10*a + 11*a - 10 *11"
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sledgehammer
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(* This equals $a^2 + a - 10*11 = a^2 + a - 110$. *)
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also have "\\<dots> = a^2 + a - 10 * 11"
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sledgehammer
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also have "\\<dots> = a^2 + a - 110"
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sledgehammer
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finally show ?thesis
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sledgehammer
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qed
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""".strip()
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}
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class MiniF2FIsabellePrompt(FewShotPrompting):
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def __init__(self):
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super().__init__()
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def format_prompt(self, task_input, task_output):
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if 'numbertheory' in task_input.split("Formal:", 1)[1]:
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tag = 'numbertheory'
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else:
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tag = 'other'
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prompt = f"{few_shot_prompt[tag].strip()}\n\n\n\nInformal:\n{task_input.strip()}\n{task_output.strip()}"
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return prompt.rstrip()
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def stop_words(self):
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return ["\nInformal:"]
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